TS EAMCET · Maths · Permutation Combination
An integer is chosen from \(\{2 k /-9 \leq k \leq 10\}\). The probability that it is divisible by both 4 and 6 is
- A \(\frac{1}{10}\)
- B \(\frac{1}{20}\)
- C \(\frac{1}{4}\)
- D \(\frac{3}{20}\)
Answer & Solution
Correct Answer
(D) \(\frac{3}{20}\)
Step-by-step Solution
Detailed explanation
Let \(S=\{2 k \mid-9 \leq k \leq 10\}=\) \(\{-18,-16,-14, \ldots, 0,2,4,6, \ldots 20\}\) Total number of possible outcomes \(=20\) Favourable outcomes are \(-12,0\) and 12 So, number of favourable outcomes \(=3\) \(\therefore\) Required probability \(=\frac{3}{20}\)
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