TS EAMCET · Maths · Straight Lines
The equation of the straight line perpendicular to \(5 x-2 y=7\) and passing through the point of intersection of the lines \(2 x+3 y=1\) and \(3 x+4 y=6\) is
- A \(2 x+5 y+17=0\)
- B \(2 x+5 y-17=0\)
- C \(2 x-5 y+17=0\)
- D \(2 x-5 y=17\)
Answer & Solution
Correct Answer
(A) \(2 x+5 y+17=0\)
Step-by-step Solution
Detailed explanation
Let the equation of line which is perpendicular to \(5 x-2 y=7\), is \(2 x+5 y=\lambda\) ...(i) Given lines are \(2 x+3 y=1\) ...(ii) and \(3 x+4 y=6\) On solving Eqs. (ii) and (iii), we get \(x=14, y=-9\) Since the Eq. (i) is passing through the point \((14,-9)\)…
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