TS EAMCET · Maths · Properties of Triangles
In a triangle ABC , if \(a=5, b=3, c=7\), then \(\sqrt{\frac{\sin (A-B)}{\sin (A+B)}}=\)
- A \(\frac{4}{7}\)
- B \(16\)
- C \(36\)
- D \(\frac{4}{5}\)
Answer & Solution
Correct Answer
(A) \(\frac{4}{7}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \sin (A+B)=\sin C \\ & \cos B=\frac{25+49-9}{2 \times 5 \times 7}=\frac{13}{14} \\ & \cos A=\frac{9+49-25}{2 \times 3 \times 7}=\frac{33}{2 \times 3 \times 7}=\frac{11}{14} \\ & \frac{\sin (A-B)}{\sin (A+B)}=\frac{\sin A \cos B-\cos A \sin B}{\sin C}…
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