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TS EAMCET · Maths · Three Dimensional Geometry

A plane passes through \((2,3,-1)\) and is perpendicular to the line having direction ratios \(3,-4,7\). The perpendicular distance from the origin to this plane is

  1. A \(\frac{3}{\sqrt{74}}\)
  2. B \(\frac{5}{\sqrt{74}}\)
  3. C \(\frac{6}{\sqrt{74}}\)
  4. D \(\frac{13}{\sqrt{74}}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{13}{\sqrt{74}}\)

Step-by-step Solution

Detailed explanation

The equation of the plane passes through the point \((2,3,-1)\) is \(a(x-2)+b(y-3)+c(z+1)=0\) ...(i) where \(a, b, c\) are the direction ratio of the normal to the plane. Also, given the plane is perpendicular to the line whose direction ratio is \((3,-4,7)\). So, that line and…
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