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TS EAMCET · Maths · Application of Derivatives

A real valued function \(f(x)=\left|x^2-3 x+2\right|+2 x-3\) is defined on \([-2,1]\). If m and M are absolute minimum and absolute maximum values of \(f\) respectively then \(\mathrm{M}-4 \mathrm{~m}=\)

  1. A \(0\)
  2. B \(1\)
  3. C \(15\)
  4. D \(10\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(10\)

Step-by-step Solution

Detailed explanation

\(f(x)=\left|x^2-3 x+2\right|+2 x-3\) For \(x \in [-2,1]\), \(x^2-3x+2=(x-1)(x-2) \ge 0\). \(f(x)=x^2-3x+2+2x-3 = x^2-x-1\) To find extremum, find derivative: \(f'(x)=2x-1\) Set \(f'(x)=0 \Rightarrow 2x-1=0 \Rightarrow x=1/2\). Evaluate \(f(x)\) at \(x=-2, 1/2, 1\):…