TS EAMCET · Maths · Properties of Triangles
In , right-angled at , the circumradius, inradius and radius of the excircle opposite to are respectively in the ratio , then the roots of the equation are
- A
- B
- C
- D
Answer & Solution
Correct Answer
(C)
Step-by-step Solution
Detailed explanation
Given that, A=90°. Circumradius R=a2sinA=a2sin90°=a2. Inradius r=s-atanA2=s-atan90°2=s-a. Exradius r1=stanA2=stan90°2=s R:r:r1=a2:s-a:s=2:5:λ ⇒a2=2⇒a=4 ⇒s-a=5⇒s-4=5⇒s=9 ∴ λ=9 Now, the equation is…
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