TS EAMCET · Maths · Properties of Triangles
If \(\triangle A B C\) is such that \(\angle A=90^{\circ}, \angle B \neq \angle \mathrm{C}\), then \(\frac{b^2+c^2}{b^2-c^2} \sin (B-C)\) is equal to
- A \(\frac{1}{3}\)
- B \(\frac{1}{2}\)
- C 1
- D \(\frac{3}{2}\)
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
Given, \(\angle A=90^{\circ}, \angle B \neq \angle C\)…
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