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TS EAMCET · Maths · Circle

The angle between the tangents drawn from the point \(\mathrm{P}(\mathrm{k}, 6 \mathrm{k})\) to the circle \(x^2+y^2+6 x-6 y+2=0\) is \(2 \operatorname{Tan}^{-1}\left(\frac{4}{3}\right)\). If the coordinates of P are integers, then \(\mathrm{k}=\)

  1. A \(1\)
  2. B \(2\)
  3. C \(3\)
  4. D \(-2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

Center of circle \(C = (-3, 3)\). Radius of circle \(r = \sqrt{3^2 + (-3)^2 - 2} = \sqrt{9+9-2} = \sqrt{16} = 4\). Given angle between tangents is \(2 \operatorname{Tan}^{-1}\left(\frac{4}{3}\right)\), so \(\tan(\theta/2) = \frac{4}{3}\). The relation for tangent angle is…