TS EAMCET · Maths · Circle
The angle between the tangents drawn from the point \(\mathrm{P}(\mathrm{k}, 6 \mathrm{k})\) to the circle \(x^2+y^2+6 x-6 y+2=0\) is \(2 \operatorname{Tan}^{-1}\left(\frac{4}{3}\right)\). If the coordinates of P are integers, then \(\mathrm{k}=\)
- A \(1\)
- B \(2\)
- C \(3\)
- D \(-2\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
Center of circle \(C = (-3, 3)\). Radius of circle \(r = \sqrt{3^2 + (-3)^2 - 2} = \sqrt{9+9-2} = \sqrt{16} = 4\). Given angle between tangents is \(2 \operatorname{Tan}^{-1}\left(\frac{4}{3}\right)\), so \(\tan(\theta/2) = \frac{4}{3}\). The relation for tangent angle is…
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