TS EAMCET · Maths · Limits
\(\lim _{\theta \rightarrow \frac{\pi}{2}^{-}} \frac{8 \tan ^4 \theta+4 \tan ^2 \theta+5}{(3-2 \tan \theta)^4}=\)
- A \(-\frac{1}{2}\)
- B \(\frac{1}{2}\)
- C -4
- D 1
Answer & Solution
Correct Answer
(B) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \lim _{\theta \rightarrow \frac{\pi^{-}}{2}} \frac{8 \tan ^4 \theta+4 \tan ^2 \theta+5}{(3-2 \tan \theta)^4} \quad \mathrm{[Using L'Hopital]} \\ & =\lim _{\theta \rightarrow \frac{\pi^{-}}{2}} \frac{\left(4 \tan ^2 \theta+1\right) \tan \theta}{(2 \tan…
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