TS EAMCET · Maths · Trigonometric Ratios & Identities
\(\frac{1}{\sin 250^{\circ}}+\frac{\sqrt{3}}{\cos 290^{\circ}}=\)
- A \(\frac{1}{\sqrt{3}}\)
- B 4
- C \(\frac{4}{\sqrt{3}}\)
- D 1
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {Given } \frac{1}{\sin 250^{\circ}}+\frac{\sqrt{3}}{\cos 290^{\circ}} \\ & =\frac{1}{\sin \left(270^{\circ}-20^{\circ}\right)}+\frac{\sqrt{3}}{\cos \left(270^{\circ}+20^{\circ}\right)} \\ & =-\frac{1}{\cos 20^{\circ}}+\frac{\sqrt{3}}{\sin 20^{\circ}} \\ &…
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