TS EAMCET · Maths · Circle
The radius of the circle with the polar equation \(r^2-8 r(\sqrt{3} \cos \theta+\sin \theta)+15=0\) is
- A \(8\)
- B \(7\)
- C \(6\)
- D \(5\)
Answer & Solution
Correct Answer
(B) \(7\)
Step-by-step Solution
Detailed explanation
Given polar equation of circle is \[ r^2-8 r(\sqrt{3} \cos \theta+\sin \theta)+15=0 \] or \(r^2-8(\sqrt{3} r \cos \theta+r \sin \theta)+15=0\) where \(r \cos \theta=x\) and \(y=r \sin \theta\). It can be rewritten in cartesian form…
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