TS EAMCET · Chemistry · Thermodynamics (C)
What will be the \(\Delta U\) value, when one mole of oxygen \(\left(\mathrm{O}_2\right)\) is going from \(-20^{\circ} \mathrm{C}\) to \(40^{\circ} \mathrm{C}\) at constant volume? (Molar heat capacity for oxygen \(\simeq 20.8 \mathrm{~J}\) \(\left.\mathrm{mol}^{-1} \mathrm{~K}^{-1}\right)\)
- A \(2496 \mathrm{~J}\)
- B \(20.8 \mathrm{~J}\)
- C \(416 \mathrm{~J}\)
- D \(1248 \mathrm{~J}\)
Answer & Solution
Correct Answer
(D) \(1248 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(\because\) Given, Molar heat capacity for oxygen \(=20.8 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) \(Q=n C \Delta T\) where, \(Q=\) value of \(\Delta U\) in \(\mathrm{J}\) \(n=\text { number of moles }(=1)\) \(C=\text { heat capacity }\) \(\Delta T=\) temperature…
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