TS EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
Ammonia on reaction with chlorine forms an explosive \(\mathrm{NCl}_3\). What is the mole ratio of \(\mathrm{NH}_3\) and \(\mathrm{Cl}_2\) required for this reaction?
- A \(8: 3\)
- B \(1: 1\)
- C \(1: 3\)
- D \(10: 1\)
Answer & Solution
Correct Answer
(C) \(1: 3\)
Step-by-step Solution
Detailed explanation
The balanced equation is \[ \mathrm{NH}_3+3 \mathrm{Cl}_2 \longrightarrow \mathrm{NCl}_3+3 \mathrm{HCl} \] Thus, the ratio of \(\mathrm{NH}_3\) to \(3 \mathrm{Cl}_2\) is \(1: 3\).
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