TS EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
What is the correct order of atomic radius of \(\mathrm{Al}, \mathrm{Na}, \mathrm{B}\) and \(\mathrm{Be} ?\)
- A \(\mathrm{Be} < \mathrm{Na} < \mathrm{Al} < \mathrm{B}\)
- B \(\mathrm{B} < \mathrm{Be} < \mathrm{Al} < \mathrm{Na}\)
- C \(\mathrm{Al} < \mathrm{Be} < \mathrm{B} < \mathrm{Na}\)
- D \(\mathrm{Na} < \mathrm{Al} < \mathrm{B} < \mathrm{Be}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{B} < \mathrm{Be} < \mathrm{Al} < \mathrm{Na}\)
Step-by-step Solution
Detailed explanation
So, \(\mathrm{B} < \mathrm{Be} < \mathrm{Al} < \mathrm{Na}\) is the correct order of atomic radius because along a period atomic radius decreases but the group atomic radius increases.
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