TS EAMCET · Chemistry · Chemical Equilibrium
\(\mathrm{PCl}_5 \rightleftharpoons \mathrm{PCl}_3+\mathrm{PCl}_2\) If the equilibrium constant \(\left(K_C\right)\) for the above reaction at \(500 \mathrm{~K}\) is 1.79 and the equilibrium concentration of \(\mathrm{PCl}_5\) and \(\mathrm{PCl}_3\) are \(1.41 \mathrm{M}\) and \(1.59 \mathrm{M}\), respectively, then the concentration of \(\mathrm{Cl}_2\) is approximately.
- A \(1.26 \mathrm{M}\)
- B \(3.59 \mathrm{M}\)
- C \(0.59 \mathrm{M}\)
- D \(1.59 \mathrm{M}\)
Answer & Solution
Correct Answer
(D) \(1.59 \mathrm{M}\)
Step-by-step Solution
Detailed explanation
Equilibrium constant \(\left(K_C\right)=\frac{\left[\mathrm{PCI}_3\right]\left[\mathrm{CI}_2\right]}{\left[\mathrm{PCI}_5\right]}\)…
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