TS EAMCET · Chemistry · Chemical Kinetics
For a reaction, \(A \rightarrow B\), the average energies of \(A\) and \(B\) are 30 and \(60 \mathrm{kcal} / \mathrm{mol}\) respectively. Energy of the activation for the backward reaction is \(93 \mathrm{kcal} / \mathrm{mol}\). The energy of activation for the forward reaction is
- A \(30 \mathrm{kcal} / \mathrm{mol}\)
- B \(123 \mathrm{kcal} / \mathrm{mol}\)
- C \(153 \mathrm{kcal} / \mathrm{mol}\)
- D \(90 \mathrm{kcal} / \mathrm{mol}\)
Answer & Solution
Correct Answer
(B) \(123 \mathrm{kcal} / \mathrm{mol}\)
Step-by-step Solution
Detailed explanation
Activation energy is the energy that must be provided to compound to result in a chemical reaction. Given, for the reaction \(A \longrightarrow B\). \(E_b\) or average energy of \((A)=30 \mathrm{kcal} / \mathrm{mol}\) Average energy of \((B)=60 \mathrm{kcal} / \mathrm{mol}\) and…
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