TS EAMCET · Chemistry · d and f Block Elements
The correct order of the increasing magnetic moments for the following ions is \(\mathrm{NiCl}_4^{2-} ; \mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+} ; \mathrm{Ni}(\mathrm{CN})_4^{2-} ; \mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+}\)
- A \(\mathrm{Ni}(\mathrm{CN})_4^{2-} < \mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+} < \mathrm{NiCl}_4^{2-} < \mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+}\)
- B \(\mathrm{NiCl}_4^{2-} < \mathrm{Ni}(\mathrm{CN})_4^{2-} < \mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+} < \mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+}\)
- C \(\mathrm{Ni}(\mathrm{CN})_4^{2-} < \mathrm{NiCl}_4^{2-} < \mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+} < \mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+}\)
- D \(\mathrm{Ni}(\mathrm{CN})_4^{2-} < \mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+} < \mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+} < \mathrm{NiCl}_4^{2-}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{Ni}(\mathrm{CN})_4^{2-} < \mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+} < \mathrm{NiCl}_4^{2-} < \mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6^{2+}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{NiCl}_4^{2-}\) is paramagnetic but \(\mathrm{Ni}(\mathrm{CN})_4^{2-}\) is diamagnetic because \(\mathrm{CN}\) is strong ligand, in excited state electrons get paired and no electrons of \(\mathrm{Ni}\) remain unpaired. While \(\mathrm{Cl}\) is weak ligand and two…
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