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TS EAMCET · Chemistry · Solutions

At \(298 \mathrm{~K}\) the molar solubility of \(\mathrm{Cd}(\mathrm{OH})_2\) in \(0.1 \mathrm{M} \mathrm{KOH}\) solution is \(x \times 10^{-\mathrm{y}}\). The values of \(x\) and \(y\) are respectively (at \(298 \mathrm{~K}, \mathrm{~K}_{\mathrm{sp}}\) of \(\mathrm{Cd}(\mathrm{OH})_2=2.5 \times 10^{-14}\) )

  1. A \(2.5,14\)
  2. B 25,13
  3. C 25,14
  4. D \(2.5,16\)
Verified Solution

Answer & Solution

Correct Answer

(B) 25,13

Step-by-step Solution

Detailed explanation

\(\mathrm{KOH} \rightarrow \mathrm{K}^{+}+\mathrm{OH}^{-}\) \(\mathrm{Cd}(\mathrm{OH})_2 \rightleftharpoons \begin{array}{cc}0.1 & 0.1 \\ \mathrm{Cd}^{2+} & +2 \mathrm{OH}^{-} \\ \mathrm{S} & 2 \mathrm{~S}\end{array}\) Solubility product…