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TS EAMCET · Chemistry · Structure of Atom

The wavelength (in \(Å\) ) of a photon having energy \(3 \mathrm{eV}\) is approximately. \[ \begin{aligned} & {\left[1 \mathrm{eV}=1.6 \times 10^{12} \mathrm{erg}\right]} \ & {\left[h=6.626 \times 10^{27} \mathrm{erg} \mathrm{s}\right]} \end{aligned} \]

  1. A 3000
  2. B 4000
  3. C 4141
  4. D 7824
Verified Solution

Answer & Solution

Correct Answer

(C) 4141

Step-by-step Solution

Detailed explanation

\(3 \mathrm{eV}=3 \times 1.6 \times 10^{-12} \mathrm{erg}=\) Energy \((E)\) \[ \lambda=\frac{h c}{E}=\frac{6.626 \times 10^{-27} \times 3 \times 10^8}{3 \times 1.6 \times 10^{-22}}=4141(Å) \]