TS EAMCET · Chemistry · Structure of Atom
The wavelength (in \(Å\) ) of a photon having energy \(3 \mathrm{eV}\) is approximately. \[ \begin{aligned} & {\left[1 \mathrm{eV}=1.6 \times 10^{12} \mathrm{erg}\right]} \ & {\left[h=6.626 \times 10^{27} \mathrm{erg} \mathrm{s}\right]} \end{aligned} \]
- A 3000
- B 4000
- C 4141
- D 7824
Answer & Solution
Correct Answer
(C) 4141
Step-by-step Solution
Detailed explanation
\(3 \mathrm{eV}=3 \times 1.6 \times 10^{-12} \mathrm{erg}=\) Energy \((E)\) \[ \lambda=\frac{h c}{E}=\frac{6.626 \times 10^{-27} \times 3 \times 10^8}{3 \times 1.6 \times 10^{-22}}=4141(Å) \]
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