TS EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
The successive ionisation energies (starting from the \(1^{\text {st }}\) ) of anelementare \(801,2430,3660,25,000\) and \(32,800 \mathrm{~kJ} \mathrm{~mol}^{-1}\), respectively. The element is
- A \(\mathrm{B}\)
- B \(\mathrm{C}\)
- C \(\mathrm{O}\)
- D \(\mathrm{N}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{B}\)
Step-by-step Solution
Detailed explanation
There are five successive ionization energies means 5 electrons are successively removed. Therefore, the atomic no. of the element is 5 . \(\therefore \quad\) The element is ' \(\mathrm{B}\) '.
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