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TS EAMCET · Chemistry · Ionic Equilibrium

The pH of pure water at 80°C is

  1. A 7.0
  2. B
  3. C >7.0
  4. D <7.0
Verified Solution

Answer & Solution

Correct Answer

(D) <7.0

Step-by-step Solution

Detailed explanation

At 25°C, the value of the ionic product of water is10-14. The ionic product of water is defined as Kw=H+OH-⇒10-14=H+OH-For pure water H+=OH-So H+=10-7Thus the pH=7 Since the degree of ionization is proportional to temperature, the value…