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TS EAMCET · Chemistry · Hydrogen

\(\mathrm{BeH}_2\) can be prepared by the reaction of

  1. A \(\mathrm{BeCl}_2\) with \(\mathrm{LiAlH}_4\)
  2. B Be with \(\mathrm{H}_2\)
  3. C Be with water
  4. D Be with liquid ammonia
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{BeCl}_2\) with \(\mathrm{LiAlH}_4\)

Step-by-step Solution

Detailed explanation

When \(\mathrm{BeCl}_2\) reduced in presence of \(\mathrm{LiAlH}_4\) then we obtained \(\mathrm{BeH}_2\). \[ \mathrm{BeCl}_2 \xrightarrow{\stackrel{4[\mathrm{H}]}{\mathrm{LiAlH}_4} \xrightarrow{\longrightarrow}} \mathrm{BeH}_2+2 \mathrm{HCl} \]