TS EAMCET · Chemistry · Redox Reactions
The oxidation state of \(\mathrm{Xe}\) in \(\mathrm{XeO}_3\) and the bond angle in it respectively are:
- A \(+6,109^{\circ}\)
- B \(+8,103^{\circ}\)
- C \(+6,103^{\circ}\)
- D \(+8,120^{\circ}\)
Answer & Solution
Correct Answer
(C) \(+6,103^{\circ}\)
Step-by-step Solution
Detailed explanation
The oxidation state of \(\mathrm{Xe}\) in \(\mathrm{XeO}_3\) can be calculate as \(\mathrm{XeO}_3, x+(-2 \times 3)=0\) \(x=+6\) \(\mathrm{XeO}_3\) has \(s p^3\)-hybridisation with bond angle \(=103^{\circ}\)
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