TS EAMCET · Maths · Three Dimensional Geometry
If \((1,0,3),(2,1,5),(-2,3,6)\) are the mid-points of the sides of a triangle, then the centroid of the triangle is
- A \(\left(\frac{1}{3}, \frac{4}{3},-\frac{14}{3}\right)\)
- B \(\left(\frac{1}{3}, \frac{4}{3}, \frac{14}{3}\right)\)
- C \(\left(\frac{1}{3},-\frac{4}{3}, \frac{14}{3}\right)\)
- D \(\left(-\frac{1}{3}, \frac{4}{3}, \frac{14}{3}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{1}{3}, \frac{4}{3}, \frac{14}{3}\right)\)
Step-by-step Solution
Detailed explanation
We have, \((1,0,3),(2,1,5),(-2,3,6)\) is mid point of the sides of triangle. Centroid of \(\triangle A B C\) is also the centroid of \(\triangle D E F\)…
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