TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The number of lone pair of electrons present in the valence shell of Xenon \((\mathrm{z}=54)\) in \(\mathrm{XeOF}_4, \mathrm{XeF}_4, \mathrm{XeF}_2\) and \(\mathrm{XeF}_6\) are respectively
- A \(1,2,3,1\)
- B \(2,1,2,2\)
- C \(3,1,2,1\)
- D \(1,3,2,0\)
Answer & Solution
Correct Answer
(A) \(1,2,3,1\)
Step-by-step Solution
Detailed explanation
\(\mathrm{Xe}\) in \(\mathrm{XeOF}_4\) forms one \(\mathrm{Xe}=0\) double bond and four \(\mathrm{Xe}-\mathrm{F}\) single bonds using six of its eight valence electrons. The remaining two valence electrons form one lone pair. Similarly, there are two, three and one lone pairs in…
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