TS EAMCET · Maths · Statistics
Let be the mean deviation of the first five odd natural numbers about their mean and be the mean deviation of the first five prime numbers about their mean. Then
- A
- B
- C
- D
Answer & Solution
Correct Answer
(B)
Step-by-step Solution
Detailed explanation
O=∑i=1nxi-xn, where x1=1, x2=3, x3=5, x4=7, x5=9 x=1+3+5+7+95=5 So, O=5-1+5-3+5-5+5-7+5-95 ⇒O=125=2.4 P=∑i=1nyi-yn, where y1=2, y2=3, y3=5, y4=7, y5=11 y=2+3+5+7+115=285=5.6 So, P=2-5.6+3-5.6+5-5.6+7-5.6+11-5.65 ⇒P=13.65=2.72 So, P-O=2.72-2.4=0.32
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