TS EAMCET · Chemistry · Haloalkanes and Haloarenes

Match the following:

The correct answer is $\begin{array}{lll} \text { A } & \text { B } & \text { C } & \text{D} \end{array}$

A I II III IV
B IV II III I
C IV I II III
D IV II I III

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Answer & Solution

Correct Answer

(C) IV I II III

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Detailed explanation

p-alkylhalide undergoes SN2 reaction with $\mathrm{KOH}$ in high dielectric medium like water and undergoes $\mathrm{E}_2$ reaction in less dielectric medium like alcohol. In acidic medium - $\mathrm{OH}$ group is protonated in order to form a better leaving group,…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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From TS EAMCET

x_{1}, x_{2}, \dots, x_{n}

are

n

observations with mean

\bar{x}

and standard deviation

σ

. Match the items of List-I with those of List-II

	List - I		List - II
(a)	$\sum_{i = 1}^{n} (x_{i} - \bar{x})$	(i)	Median
(b)	Variance $(σ^{2})$	(ii)	Coefficient of variation
(c)	Mean deviation	(iiii)	Zero
(d)	Measure used to find the homogeneity of given two series	(iv)	Mean of the absolute deviations from any measure of central tendency
		(v)	Mean of the squares of the deviations from mean

TS EAMCET 2018 Hard

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Match the following:

The correct answer is \(\begin{array}{lll} \text { A } & \text { B } & \text { C } & \text{D} \end{array}\)

Answer & Solution

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Match the following:The correct answer is \(\begin{array}{lll} \text { A } & \text { B } & \text { C } & \text{D} \end{array}\)

Step-by-step Solution

Match the following:

The correct answer is \(\begin{array}{lll} \text { A } & \text { B } & \text { C } & \text{D} \end{array}\)