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The experimental depression in freezing point of a dilute solution is $0.025 \mathrm{~K}$. If the van't Hoff factor (i) is 2.0 , the calculated depression in freezing point (in $\mathrm{K}$ ) is

A 0.00125
B 0.025
C 0.0125
D 0.05

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Answer & Solution

Correct Answer

(C) 0.0125

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Detailed explanation

Given, depression in freezing point of a dilute solution is $0.025 \mathrm{~K}$. \[ i=2.0 \] van't Hoff factor \[ \text { (i) }=\frac{\text { Observed colligative property (experimental) }}{\text { Calculated colligative property }} \]…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match the reactants in List-I with the products in List-II.

	List - I		List - II
(a)	$H_{2} O + H_{2} S$	(i)	$(H_{3} O^{+}, {HS}^{-})$
(b)	$H_{2} O + N^{3 -}$	(ii)	$({NH}_{3}, {OH}^{-})$
(c)	$H_{2} O + {SiCl}_{4}$	(iii)	$({OH}^{-}, H_{3} S^{+})$
(d)	$H_{2} O + F_{2}$	(iv)	$({SiO}_{2}, HCl)$
		(v)	$({SiO}_{4}^{4}, {Cl}_{2})$
		(vi)	$(O_{2}, F^{-})$
		(vii)	$(HF, {OH}^{-})$
		(viii)	$({OH}^{-}, {HN}_{3})$

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The experimental depression in freezing point of a dilute solution is \(0.025 \mathrm{~K}\). If the van't Hoff factor (i) is 2.0 , the calculated depression in freezing point (in \(\mathrm{K}\) ) is

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