TS EAMCET · Chemistry · Ionic Equilibrium
The concentration in \(M\) of \(\mathrm{OH}^{-}\)in \(0.001 \mathrm{M}\) \(\mathrm{H}_2 \mathrm{SO}_4\) is
- A \(1 \times 10^{-13}\)
- B \(0.5 \times 10^{-12}\)
- C \(5 \times 10^{-12}\)
- D \(0.5 \times 10^{-13}\)
Answer & Solution
Correct Answer
(C) \(5 \times 10^{-12}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{H}_2 \mathrm{SO}_4(0.001 \mathrm{M}) \rightleftharpoons 2 \mathrm{H}^{+}+\mathrm{SO}_4^{2-}\) Concentration of \(\mathrm{H}^{+}=2 \times 0.001 \mathrm{M}=0.002 \mathrm{M}\)…
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