TS EAMCET · Maths · Probability
Three groups of children A B, and C contains boys and girls as given below. Group A contains 3 girls and one boy, group B contains 2 girls and 2 boys and group C contains 3 boys and 1 girl. One child is selected at random from each group. The probability that the three children selected are 1 girl and 2 boys is
- A \(\frac{9}{32}\)
- B \(\frac{3}{32}\)
- C \(\frac{13}{32}\)
- D \(\frac{19}{32}\)
Answer & Solution
Correct Answer
(C) \(\frac{13}{32}\)
Step-by-step Solution
Detailed explanation
\(\frac{\text { Group (1) }}{3 G, 1 B} \frac{\text { Group (2) }}{2 G, 2 B} \frac{\text { Group (3) }}{1 G, 3 B}\) \(\because\) Probability \(=\frac{\text { favourable outcome }}{\text { Total outcome }}\) For selecting: \begin{array}{lll} \hline Group (1) & Group (2) & Group…
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