TS EAMCET · Chemistry · Some Basic Concepts of Chemistry
The average molecular weight of the air which has \(21 \%\) of \(\mathrm{O}_2\) and \(79 \%\) of \(\mathrm{N}_2\), is
- A 44.8
- B 100
- C 14.4
- D 28.8
Answer & Solution
Correct Answer
(D) 28.8
Step-by-step Solution
Detailed explanation
Average molecular weight \(=21 \%\) of \(\mathrm{O}_2+79 \%\) of \(\mathrm{N}_2\) \[ \begin{aligned} & \Rightarrow \quad \frac{21}{100} \times 32+\frac{79}{100} \times 28 \\ & \Rightarrow \quad 6.72+22.12=28.8 \end{aligned} \]
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