The consequence of global warming may be the following

Which of the following is a lung irritant that can lead to an acute respiratory disease in children?

\(10 \mathrm{~g}\) of a radioactive element is disintegrated to \(1 \mathrm{~g}\) in 2.303 minutes. What is the half-life (in minutes) of that radioactive element?

$1 \mathrm{L}$ each of gases $\mathrm{A}$ and $\mathrm{B}$ diffused through a membrane in $15$ and $30$ minutes, respectively, under identical conditions. What is the ratio of molecular weight of $\mathrm{A}$ and $\mathrm{B}?$

\[ \begin{aligned} & \text { Given } \mathrm{H}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{H}_2 \mathrm{O}(l) ; \Delta \mathrm{H}=-285 \mathrm{~kJ} \ & \mathrm{~N}_2 \mathrm{O}_5(\mathrm{~g})+\mathrm{H}_2 \mathrm{O}(l) \rightarrow 2 \mathrm{HNO}_3(l) ; \Delta \mathrm{H}=-76.6 \mathrm{~kJ} \ & \mathrm{~N}_2(\mathrm{~g})+3 \mathrm{O}_2(\mathrm{~g})+\mathrm{H}_2(\mathrm{~g}) \rightarrow 2 \mathrm{HNO}_3(l) ; \Delta \mathrm{H}=-348.2 \mathrm{~kJ} \ & \text { Calculate the } \Delta \mathrm{H} \text { of } 2 \mathrm{~N}_2(\mathrm{~g})+5 \mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{~N}_2 \mathrm{O}_5(\mathrm{~g}) \end{aligned} \] Calculate the \(\Delta \mathrm{H}\) of \(2 \mathrm{~N}_2(\mathrm{~g})+5 \mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{~N}_2 \mathrm{O}_5(\mathrm{~g})\).

The major product formed by the reaction of benzylamine with nitrous acid is

Which one of the following is not an ambidentate ligand?

If the circle \(S_1: x^2+y^2=16\) intersects another circle \(S_2\) of radius 5 units such that the common chord is of maximum length and slope \(\frac{3}{4}\), then the centre of the circle \(S_2\) is

Let $L_1, L_2$ be the lines represented by the equation $4x^2-5xy+3y^2=0$. Let $L_3, L_4$ be two lines passing through the point $\left(4,3\right)$ such that $L_3$ and $L_4$ are perpendicular to $L_1$ and $L_2$ respectively. If the combined equation of $L_3$ and $L_4$ is $a{x}^2+2hxy+b{y}^2+2gx+2fy+c=0$, then $af+bg+ch=$

The shortest wavelength in Lyman series is \(912 Å\). Then, the longest wavelength in the series must be

Given ${\mathrm{\lambda }°}_{{\mathrm{Mg}}^{2+}}=106 \mathrm{S}{ \mathrm{cm}}^2{ \mathrm{mole}}^{-1}, {\mathrm{\lambda }°}_{{\mathrm{SO}}_4^{2-}}=160 \mathrm{S}{ \mathrm{cm}}^2{ \mathrm{mole}}^{-1}.$ The value of ${\mathrm{\lambda }°}_{{\mathrm{MgSO}}_4}$ (in $\mathrm{S} {\mathrm{cm}}^2 {\mathrm{mole}}^{-1}$)  is

Number of all possible words (with or without meaning) that can be formed using all the letters of the word CABINET in which neither the word CAB nor the word NET appear is

\(\int\left(\frac{1-\log x}{1+(\log x)^2}\right)^2 d x=\)