TS EAMCET · Chemistry · Some Basic Concepts of Chemistry
Sulphuric acid reacts with sodium hydroxide as follows : \(\mathrm{H}_2 \mathrm{SO}_4+2 \mathrm{NaOH} \longrightarrow \mathrm{Na}_2 \mathrm{SO}_4+2 \mathrm{H}_2 \mathrm{O}\) What will be the amount of sodium sulphate formed, when \(1 \mathrm{~L}\) of \(0.2 \mathrm{M}\) sulphuric acid is allowed to react with \(1 \mathrm{~L}\) of \(0.2 \mathrm{M}\) sodium hydroxide solution?
- A 4.5 g
- B 142 g
- C 14.2 g
- D 1.42 g
Answer & Solution
Correct Answer
(C) 14.2 g
Step-by-step Solution
Detailed explanation
\(\mathrm{H}_2 \mathrm{SO}_4+2 \mathrm{NaOH} \longrightarrow \mathrm{Na}_2 \mathrm{SO}_4+2 \mathrm{H}_2 \mathrm{O}\) Stoichiometry \(\Rightarrow 1 \mathrm{~mol} \quad 2 \mathrm{~mol} \quad 1 \mathrm{~mol}\) Mole at \(t=0 \Rightarrow 1 \times 0.2 \quad 1 \times 0.2 \quad 0\)…
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