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TS EAMCET · Chemistry · Some Basic Concepts of Chemistry

Sulphuric acid reacts with sodium hydroxide as follows : \(\mathrm{H}_2 \mathrm{SO}_4+2 \mathrm{NaOH} \longrightarrow \mathrm{Na}_2 \mathrm{SO}_4+2 \mathrm{H}_2 \mathrm{O}\) What will be the amount of sodium sulphate formed, when \(1 \mathrm{~L}\) of \(0.2 \mathrm{M}\) sulphuric acid is allowed to react with \(1 \mathrm{~L}\) of \(0.2 \mathrm{M}\) sodium hydroxide solution?

  1. A 4.5 g
  2. B 142 g
  3. C 14.2 g
  4. D 1.42 g
Verified Solution

Answer & Solution

Correct Answer

(C) 14.2 g

Step-by-step Solution

Detailed explanation

\(\mathrm{H}_2 \mathrm{SO}_4+2 \mathrm{NaOH} \longrightarrow \mathrm{Na}_2 \mathrm{SO}_4+2 \mathrm{H}_2 \mathrm{O}\) Stoichiometry \(\Rightarrow 1 \mathrm{~mol} \quad 2 \mathrm{~mol} \quad 1 \mathrm{~mol}\) Mole at \(t=0 \Rightarrow 1 \times 0.2 \quad 1 \times 0.2 \quad 0\)…