TS EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
One mole of fluorine is reacted with two moles of hot concentrated \(\mathrm{KOH}\). The products formed are \(\mathrm{KF}, \mathrm{H}_2 \mathrm{O}\) and \(\mathrm{O}_2\). The molar ratio of \(\mathrm{KF}, \mathrm{H}_2 \mathrm{O}\) and \(\mathrm{O}_2\), respectively is
- A \(1: 1: 2\)
- B \(2: 1: 0.5\)
- C \(1: 2: 1\)
- D \(2: 1: 2\)
Answer & Solution
Correct Answer
(B) \(2: 1: 0.5\)
Step-by-step Solution
Detailed explanation
Stoichiometric equation for the reaction is \[ \mathrm{F}_2+2 \mathrm{KOH} \longrightarrow 2 \mathrm{KF}+\mathrm{H}_2 \mathrm{O}+\frac{1}{2} \mathrm{O}_2 \]
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