TS EAMCET · Chemistry · Chemical Equilibrium
One mole of \(A(g)\) is heated to \(200^{\circ} \mathrm{C}\) in a one litre closed flask, till the following equilibrium is reached. \(A(g) \quad B(g)\) The rate of forward reaction at equilibrium is \(0.02 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}\). What is the rate (in \(\mathrm{mol} \mathrm{L}^{-1} \mathrm{~min}^{-1}\) ) of the backward reaction at equilibrium?
- A \(0.04\)
- B \(0.01\)
- C \(0.02\)
- D \(1\)
Answer & Solution
Correct Answer
(C) \(0.02\)
Step-by-step Solution
Detailed explanation
At equilibrium, rate of forward reaction \(=\) rate of backward reaction \(\therefore\) rate of backward reaction at equilibrium \(=0.02 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}\)
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