TS EAMCET · Chemistry · Redox Reactions
In which of the following, ions are correctly arranged in the increasing order of oxidizing power?
- A \(\mathrm{Cr}_2 \mathrm{O}_7^{2-} \lt \mathrm{MnO}_4^{-} \lt \mathrm{VO}_2^{+}\)
- B \(\mathrm{VO}_2^{+} \lt \mathrm{Cr}_2 \mathrm{O}_7^{2-} \lt \mathrm{MnO}_4^{-}\)
- C \(\mathrm{VO}_2^{+} \lt \mathrm{MnO}_4^{-} \lt \mathrm{Cr}_2 \mathrm{O}_7^{2-}\)
- D \(\mathrm{MnO}_4^{-} \lt \mathrm{Cr}_2 \mathrm{O}_7^{2-} \lt \mathrm{VO}_2^{+}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{VO}_2^{+} \lt \mathrm{Cr}_2 \mathrm{O}_7^{2-} \lt \mathrm{MnO}_4^{-}\)
Step-by-step Solution
Detailed explanation
The oxidation state of the various transition elements are \(\mathrm{V}=+5, \mathrm{Mn}=+7, \mathrm{Cr}-+6\) Oxidizing power depends upon the stability of the reduction product obtained. Since lower oxides of Mn are more stable than that of Cr and V . So the order of increasing…
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