TS EAMCET · Chemistry · Structure of Atom

In an atom the order of increasing energy of electrons with quantum numbers (i) \(n=4, l=1\) (ii) \(n=4, l=0\) (iii) \(n=3, l=2\) and (iv) \(n=3, l=1\) is

A \(\mathrm{iii} < \) (i) \( < \mathrm{iv} < \) ii
B \(\mathrm{ii} < \mathrm{iv} < \mathrm{i} < \mathrm{iii}\)
C \(\mathrm{i} < \mathrm{iii} < \mathrm{ii} < \mathrm{iv}\)
D iv \( < \mathrm{ii} < \mathrm{iii} < \mathrm{i}\)

Verified Solution

Answer & Solution

Correct Answer

(D) iv \( < \mathrm{ii} < \mathrm{iii} < \mathrm{i}\)

Step-by-step Solution

Detailed explanation

The order of increase of energy can be calculated from \((n+I)\) rule. If two orbitals have same value of \((n+I)\), the orbital with lower value of \(n\) will be filled first. (i) For \(n=4, I=1,(n+I)=4+1=5\) (ii) For \(n=4, l=0,(n+l)=4+0=4\) (iii) For \(n=3, l=2,(n+l)=3+2=5\)…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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