TS EAMCET · Chemistry · Chemical Kinetics
Consider the gaseous reaction \(\mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB}\)
The following data was obtained for the above reaction.

The value of rate constant for the above reaction is
- A \(1.25 \times 10^{-2}\)
- B \(1.25 \times 10^{-3}\)
- C \(2.5 \times 10^{-2}\)
- D \(2.5 \times 10^{-1}\)
Answer & Solution
Correct Answer
(A) \(1.25 \times 10^{-2}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB}\) \(\text { Rate }=-\frac{\mathrm{d}\left[\mathrm{~A}_2\right]}{\mathrm{dt}}=-\frac{\mathrm{d}\left[\mathrm{~B}_2\right]}{\mathrm{dt}}=\frac{1 \mathrm{~d}}{2} \frac{[\mathrm{AB}]}{\mathrm{dt}}\) First we have to calculate…
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