TS EAMCET · Chemistry · Thermodynamics (C)
Average \(\mathrm{C}-\mathrm{H}\) bond energy is \(416 \mathrm{~kJ} \mathrm{~mol}^{-1}\). Which of the following is correct?
- A \(\mathrm{CH}_4(g)+416 \mathrm{~kJ} \longrightarrow \mathrm{C}(g)+4 \mathrm{H}(g)\)
- B \(\mathrm{CH}_4(g) \longrightarrow \mathrm{C}(g)+4 \mathrm{H}(g)+416 \mathrm{~kJ}\)
- C \(\mathrm{CH}_4(g)+1664 \mathrm{~kJ} \longrightarrow \mathrm{C}(g)+4 \mathrm{H}(g)\)
- D \(\mathrm{CH}_4(g) \longrightarrow \mathrm{C}(g)+4 \mathrm{H}(g)+1664 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{CH}_4(g)+1664 \mathrm{~kJ} \longrightarrow \mathrm{C}(g)+4 \mathrm{H}(g)\)
Step-by-step Solution
Detailed explanation
\(\mathrm{CH}_4\) has four \(\mathrm{C}-\mathrm{H}\) bonds. So, \(4 \times 416=1664 \mathrm{~kJ}\) is required to break \(\mathrm{CH}_4\) into \(\mathrm{C}\) and \(4 \mathrm{H}\).
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