TS EAMCET · Chemistry · Chemical Bonding and Molecular Structure
Arrange the molecules \(\mathrm{B}_2, \mathrm{He}_2, \mathrm{~N}_2\) and \(\mathrm{C}_2\) in the increasing order of their bond order values
- A \(\mathrm{C}_2 < \mathrm{He}_2 < \mathrm{B}_2 < \mathrm{N}_2\)
- B \(\mathrm{N}_2 < \mathrm{B}_2 < \mathrm{C}_2 < \mathrm{He}_2\)
- C \(\mathrm{He}_2 < \mathrm{B}_2 < \mathrm{C}_2 < \mathrm{N}_2\)
- D \(\mathrm{He}_2 < \mathrm{C}_2 < \mathrm{N}_2 < \mathrm{B}_2\)
Answer & Solution
Correct Answer
(C) \(\mathrm{He}_2 < \mathrm{B}_2 < \mathrm{C}_2 < \mathrm{N}_2\)
Step-by-step Solution
Detailed explanation
Bond order can be calculated by using the formula, B. \(\mathrm{O} .=\frac{1}{2}\left[\mathrm{~N}_{\mathrm{b}}-\mathrm{N}_{\mathrm{a}}\right]\) Molecular orbital electronic configuration of…
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