TS EAMCET · Maths · Binomial Theorem
If \(p\) and \(q\) are the real numbers such that the 7th term in the expansion of \(\left(\frac{5}{p^3}-\frac{3 q}{7}\right)^8\) is 700 then \(49 p^2=\)
- A \(4 q^2\)
- B \(9 q^2\)
- C \(16 q^2\)
- D \(25 q^2\)
Answer & Solution
Correct Answer
(B) \(9 q^2\)
Step-by-step Solution
Detailed explanation
\(7^{\text {th }}\) term of the expansion \(\left[\frac{5}{p^3}-\frac{3 q}{7}\right]^8=8 C_6\left(\frac{5}{p^3}\right)^2 \times\left(\frac{-3 q}{7}\right)^6\)…
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