TS EAMCET · Chemistry · Structure of Atom
Wavelength of \(\mathrm{H}^{+}\)ion with kinetic energy \(1.65 \mathrm{eV}\) is \(\left(\right.\) mass of proton \(=1.6726 \times 10^{-27} \mathrm{~kg}\) )
- A \(1.22 \mathrm{~nm}\)
- B \(0.22 \mathrm{~nm}\)
- C 0.022 nm
- D \(0.122 \mathrm{~nm}\)
Answer & Solution
Correct Answer
(C) 0.022 nm
Step-by-step Solution
Detailed explanation
Given, kinetic energy of \(\mathrm{H}^{+}\)ion \(=1.68 \mathrm{eV}\) Mass of proton \(=1.6726 \times 10^{-27} \mathrm{~kg}\) We calculate, the wavelength of \(\mathrm{H}^{+}\)ion as follows: \(\lambda=\frac{h}{\sqrt{2 E_m}}\) Here, \(E=\) kinetic energy, \(m=\) mass of proton…
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