TS EAMCET · Chemistry · Ionic Equilibrium
A solution is prepared by mixing \(10 \mathrm{~mL}\) of \(1.0 \mathrm{M}\) acetic acid and \(20 \mathrm{~mL}\) of \(0.5 \mathrm{M}\) sodium acetate and diluted to \(100 \mathrm{~mL}\). If the \(\mathrm{pK}_{\mathrm{a}}\) of acetic acid is 4.76 , then the \(\mathrm{pH}\) of the solution is
- A \(4.76\)
- B \(3.76\)
- C \(5.76\)
- D \(9.24\)
Answer & Solution
Correct Answer
(A) \(4.76\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { } \mathrm{pH}=\mathrm{pK}_{\mathrm{a}}+\log \frac{[\text { salt }]}{[\text { Acid }]} \\ & {[\text { Acid }]=\left[\mathrm{CH}_3 \mathrm{COOH}\right]=\frac{10 \times 1}{100}=0.1 \mathrm{M}} \\ & {[\text { Salt }]=\left[\mathrm{CH}_3…
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