NEET · Physics · STD 12 - 10. Wave optics
The intensity at the maximum in a Young's double slit experiment is \(I_0\). Distance between two slits is \(d = 5\lambda,\) where \(\lambda\) is the wavelength of light used in the experiment. What will be the intensity in front of one of the slits on the screen placed at a distance \(D = 10\,d\,?\)
- A \(\frac{{{I_0}}}{4}\)
- B \(\;\frac{3}{4}{I_0}\)
- C \(\;\frac{{{I_0}}}{2}\)
- D \(\;{I_0}\)
Answer & Solution
Correct Answer
(C) \(\;\frac{{{I_0}}}{2}\)
Step-by-step Solution
Detailed explanation
Here, \(d=5 \lambda\), \(D=10\,d\), \(y=\frac{d}{2}\) . Resultant Intensity at \(y=\frac{d}{2}, I_{y}=?\)
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