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NEET · Physics · STD 11 - 11. thermodynamics
The volume of \(1\; mole\) of an ideal gas with the adiabatic exponent \(\gamma\) is changed according to the relation \(V=\frac bT\) where \(b =\) constant. The amount of heat absorbed by the gas in the process if the temperature is increased by \(\triangle T\) will be
- A \(\frac{R}{{\gamma - 1}} \Delta T\)
- B \(\left( {\frac{{2 - \gamma }}{{\gamma - 1}}} \right)R \Delta T\)
- C \(\;\frac{{R \Delta T}}{{\gamma - 1}}\)
- D \(\left( {\frac{{1 - \gamma }}{{\gamma + 1}}} \right)R \Delta T\)
Answer & Solution
Correct Answer
(B) \(\left( {\frac{{2 - \gamma }}{{\gamma - 1}}} \right)R \Delta T\)
Step-by-step Solution
Detailed explanation
\(V=\frac bT\) \(VT=\)constant
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