KCET · Physics · Current Electricity
Two tangent galvanometers \(A\) and \(B\) are identical except in their number of turns. They are connected in series. On passing a current through them, deflections of \(60^{\circ}\) and \(30^{\circ}\) are produced. The ratio of the number of turns in \(A\) and \(B\) is
- A \(1: 3\)
- B \(3: 1\)
- C \(1: 2\)
- D \(2: 1\)
Answer & Solution
Correct Answer
(B) \(3: 1\)
Step-by-step Solution
Detailed explanation
As the current and the other factors are same for both the galvanometers
\(\mathrm{N} \propto \tan \theta\)
\(\frac{\mathrm{N}_{1}}{\mathrm{~N}_{2}}=\frac{\tan 60^{\circ}}{\tan 30^{\circ}}\)
\(=\frac{\sqrt{3}}{1 / \sqrt{3}}\)
\(\Rightarrow \quad \frac{\mathrm{N}_{1}}{\mathrm{~N}_{2}}=3\)
\(\mathrm{N} \propto \tan \theta\)
\(\frac{\mathrm{N}_{1}}{\mathrm{~N}_{2}}=\frac{\tan 60^{\circ}}{\tan 30^{\circ}}\)
\(=\frac{\sqrt{3}}{1 / \sqrt{3}}\)
\(\Rightarrow \quad \frac{\mathrm{N}_{1}}{\mathrm{~N}_{2}}=3\)
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