KCET · Physics · Magnetic Effects of Current
The magnetic field at the centre ' \( \mathrm{O} \) ' in the given figure is
- A \( \frac{3}{10} \mu_{0} I \)
- B \( \frac{7}{14} \mu_{0} I \)
- C \( \frac{\mu_{0} I}{12 R} \)
- D \( \frac{5}{12} \frac{\mu_{0} I}{R} \)
Answer & Solution
Correct Answer
(D) \( \frac{5}{12} \frac{\mu_{0} I}{R} \)
Step-by-step Solution
Detailed explanation
(D)
Here \( \theta=300^{\circ} \)
\( \therefore \) Number of turns \( n=\frac{300}{360}=\frac{5}{6} \)
\( B=\mu_{0} \frac{n I}{2 R} \) i.e., \( \mu_{0} \frac{5}{6} \times \frac{I}{2 R} \)
\( \therefore B=\frac{5 \mu_{0} I}{12 R} \)
Here \( \theta=300^{\circ} \)
\( \therefore \) Number of turns \( n=\frac{300}{360}=\frac{5}{6} \)
\( B=\mu_{0} \frac{n I}{2 R} \) i.e., \( \mu_{0} \frac{5}{6} \times \frac{I}{2 R} \)
\( \therefore B=\frac{5 \mu_{0} I}{12 R} \)
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