KCET · Physics · Electrostatics
The figure gives the electric potential \( V \) as a function of distance through four regions on \( x- \) axis. Which of the following is true for the magnitude of the electric field \( E \) in these regions?
- A \( E_{B}=E_{D} \) and \( E_{A} < E_{C} \)
- B \( E_{A}>E_{B}>E_{C}>E_{D} \)
- C \( E_{A} < E_{B} < E_{C} < E_{D} \)
- D \( E_{A}=E_{C} \) and \( E_{B} < E_{D} \)
Answer & Solution
Correct Answer
(D) \( E_{A}=E_{C} \) and \( E_{B} < E_{D} \)
Step-by-step Solution
Detailed explanation
In region \(\mathrm{A}, \mathrm{V}=\) constant \(\Rightarrow E_{A}=0\)
In region \(\mathrm{B}, E_{B}=\frac{4-2}{2}=1 \mathrm{vm}^{-1}\)
In region \(\mathrm{C}, \mathrm{V}=\) constant \(\mathrm{E}_{-} \mathrm{C}=0\)
In Region \(\mathrm{D}, E_{D}=\frac{4-2}{1}=2 \mathrm{vm}^{-1}\)
Here \(E_{A}=E_{C}\) and \(E_{B} < E_{D}\)
In region \(\mathrm{B}, E_{B}=\frac{4-2}{2}=1 \mathrm{vm}^{-1}\)
In region \(\mathrm{C}, \mathrm{V}=\) constant \(\mathrm{E}_{-} \mathrm{C}=0\)
In Region \(\mathrm{D}, E_{D}=\frac{4-2}{1}=2 \mathrm{vm}^{-1}\)
Here \(E_{A}=E_{C}\) and \(E_{B} < E_{D}\)
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