KCET · Physics · Electrostatics
An electric dipole with dipole moment \(4 \times 10^{-19} \mathrm{C}-\mathrm{m}\) is aligned at \(30^{\circ}\) with the direction of a uniform electric field of magnitude \(5 \times 10^4 \mathrm{NC}^{-1}\), the magnitude of the torque acting on the dipole is
- A \(\sqrt{3} \times 10^{-4} \mathrm{~N}-\mathrm{m}\)
- B \(10^{-5} \mathrm{~N}-\mathrm{m}\)
- C \(10 \times 10^{-3} \mathrm{~N}-\mathrm{m}\)
- D \(10^{-4} \mathrm{~N}-\mathrm{m}\)
Answer & Solution
Correct Answer
(D) \(10^{-4} \mathrm{~N}-\mathrm{m}\)
Step-by-step Solution
Detailed explanation
Given, for an electric dipole, dipole moment, \(p=4 \times 10^{-9} \mathrm{C}\) \(\theta=30^{\circ}\)
Magnitude of electric field, \(E=5 \times 10^4 \mathrm{~N} / \mathrm{C}\)
\(\therefore\) Torque, \(\tau=p E \sin \theta\)
\(=4 \times 10^{-9} \times 5 \times 10^4 \sin 30^{\circ}=10^{-4} \mathrm{~N}-\mathrm{m}\)
Magnitude of electric field, \(E=5 \times 10^4 \mathrm{~N} / \mathrm{C}\)
\(\therefore\) Torque, \(\tau=p E \sin \theta\)
\(=4 \times 10^{-9} \times 5 \times 10^4 \sin 30^{\circ}=10^{-4} \mathrm{~N}-\mathrm{m}\)
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