KCET · Physics · Dual Nature of Matter
Light emitted during the de excitation of electron from \(n=3\) to \(n=2\), when incident on a metal, photoelectrons are just emitted from that metal. In which of the following de excitations photoelectric effect is not possible?
- A From \(n=2\) to \(n=1\)
- B From \(n=3\) to \(n=1\)
- C From \(n=5\) to \(n=2\)
- D From \(n=4\) to \(n=3\)
Answer & Solution
Correct Answer
(D) From \(n=4\) to \(n=3\)
Step-by-step Solution
Detailed explanation
The photoelectric effect is possible when light of sufficient energy incident on metal surface. When electron de excites form \(n=3\) to \(n=2\), the light produces photoelectric effect. So for the given options, the photoelectric effect is not possible for that level in which energy of emitted light is less than that for \(n=3\) to \(n=2\).
\((h v)_{4-3} < (h v)_{3-2}\)
Hence, photoelectric effect is not possible.
\((h v)_{4-3} < (h v)_{3-2}\)
Hence, photoelectric effect is not possible.
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